openscad - 3d z dvou ploch

[Milan B.]

No nic, uz ste to nasli :)

On 19.04.2020 18:07, Milan B. wrote:
> On 19.04.2020 16:52, Jaroslav Buchta wrote:
>> ale marne patram, jak zjistit velikost vektoru (jasne da se iterovat 
>> pres vsechny prvky ale potrebuju index - no ono by to nakonec asi 
>> takhle taky slo spocitat ale rovnak na ohejbak...)
>
> Toto nevyhovuje? 
> https://en.wikibooks.org/wiki/OpenSCAD_User_Manual/Mathematical_Functions#len
>
> a=[[1,2,4],[3,4,5],[5,6,7]];
>
> n=len(a);
>
> for (i=[0:n-1]) {
>     echo(sqrt(a[i].x*a[i].x+a[i].y*a[i].y+a[i].z*a[i].z));
> }
>
>> Dne 19.04.2020 v 14:07 Pavel Hudecek napsal(a):
>>>
>>> Napsal bych si program ve VB, kterej ten polyhedron vygeneruje.
>>>
>>> PH
>>>
>>> *Od: *Jaroslav Buchta <mailto:jaroslav.buchta na hascomp.cz>
>>> *Odesláno:*neděle 19. dubna 2020 14:01
>>> *Komu: *hw-list na list.hw.cz <mailto:hw-list na list.hw.cz>
>>> *Předmět: *Re: openscad - 3d z dvou ploch
>>>
>>> No jedna se o stovky bodu, je to nasledujici tvar - to je obrys 
>>> spodni plochy, horni plocha by byla definovana podobne jen obrys 
>>> vetsi ruzne na ruznych mistech, ale jak z toho udelat polyhedron mne 
>>> nenapada...
>>>
>>>
>>> function circlepts(xc, yc, a1, a2, r, segments) =
>>> [for (i=[0:segments-1]) [
>>>         xc + r*sin(a1 + (a2-a1)/(segments-1)*i),
>>>         yc + r*cos(a1 + (a2-a1)/(segments-1)*i)]
>>> ];
>>>
>>>
>>>
>>> module basepoly()
>>> {
>>>     //translate([-132/2, -133/2])
>>>     polygon(points=concat(
>>>         [[0,0], [0,115]],
>>>         circlepts(28, 115, -90, -30, 28, 30),
>>>         circlepts(28, 115, 30, 60, 28, 30),
>>>         circlepts(63.5, 133, 240, 180, 12, 30),
>>>         [[115,121]],
>>>         circlepts(115, 116, 0, 90, 5, 10),
>>>         [[120,105]],
>>>         circlepts(115, 105, 90, 270, 5, 20),
>>>         circlepts(102, 105, 90, 0, 8, 20),
>>>         [[81,113]],
>>>         circlepts(91, 103, 0, -180, 10, 20),
>>>         circlepts(115, 100, 250, 180, 20, 30),
>>>         [[132,80], [132, 75]],
>>>         circlepts(122, 75, 90, 180, 10, 20),
>>>         [[90,65]],
>>>         circlepts(90, 30, 0, -90, 35, 30),
>>>         [[55,0]],
>>>
>>>         [[0,0]]
>>>         )
>>>     );
>>> }
>>>
>>> linear_extrude(height=20, convexity=10, scale=1.0, center = false)
>>>             basepoly();
>>>
>>> Dne 19.04.2020 v 13:52 Pavel Hudecek napsal(a):
>>>
>>>     Jestli je to nadefinované jako skupiny bodů, šlo by z toho udělat
>>>     polyhedron.
>>>
>>>     PH
>>>
>>>     *Od: *Jaroslav Buchta <mailto:jaroslav.buchta na hascomp.cz>
>>>
>>>     Dejme tomu, ze mam 2 skicy plochy slozitejsiho tvaru, jde provest
>>>     nejaka
>>>
>>>     transformace, ktera z toho udela 3D objekt ktery bude mit zakladnu
>>>
>>>     odpovidajici jedne a horni stranu druhe plose? Aby proste vznikly
>>>     sikme
>>>
>>>     steny (scale u linear_extrude nedava dobry vysledek, tvar neni
>>>     rozumne
>>>
>>>     centrovatelny)
>>>
>>>
>>>
>>>     _______________________________________________
>>>
>>>     HW-list mailing list  -  sponsored bywww.HW.cz <http://www.HW.cz>
>>>
>>>     Hw-list na list.hw.cz  <mailto:Hw-list na list.hw.cz>
>>>
>>>     http://list.hw.cz/mailman/listinfo/hw-list
>>>
>>>
>>> _______________________________________________
>>> HW-list mailing list  -  sponsored bywww.HW.cz
>>> Hw-list na list.hw.cz
>>> http://list.hw.cz/mailman/listinfo/hw-list
>>
>>
>>
>> _______________________________________________
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>> Hw-list na list.hw.cz
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>
>
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