OT: matematika

[spark]

Ano, treba uvazovat kvadrant. Tych mojich 0.03015 je vsak v 1. 
kvadrante, preto je ptorebny prepocet cez + alebo - pi, aby som sa 
dostal spat do 3. kvadrantu.

Miroslav Sinko wrote:
> Nebude to tym, ze tan je periodicka funkcia a musite brat do uvahy
> kvadrant? Vy mate zaporne obe zlozky, t.j. 3. kvadrant.
>
> http://studentigih.ttweb.sk/zemianek/tangens.html
>
> miro
>
> --- spark <quazarstar@gmail.com> wrote:
>
>   
>> abs som presne takto ziskal. Problem je vsak s agumentom.
>>
>> Galloth wrote:
>>     
>>> A co tak zkusit zjiskat abs hodnotu jako odmocninu s A^2 +B^2, kde
>>>       
>> A a
>>     
>>> B jsou imaginarni a realna slozka ( podle pythagorovi vety)?
>>>
>>> Honza
>>>
>>> 2008/2/2, spark <quazarstar@gmail.com>:
>>>   
>>>       
>>>> ahoj, mam problem s transformaciou z komplexneho cisla na
>>>>         
>> goniometricky
>>     
>>>> tvar.
>>>> x = -86799160.01 -j2663767.425
>>>> Postup je klasicky, ziskat absolutnu hodnotu a argument, argument
>>>>         
>> sa
>>     
>>>> ziskava ako
>>>> fi = atan( Im/Re ), alebo nie ??
>>>> x = 86840024.39 * ( cos( 0.03067 ) +j sin( 0.03067 ) )
>>>> ako som vsak zistil, argument nema byt 0.03067 ale 0.03067 - pi =
>>>>         
>> -3.1109
>>     
>>>> A tu je ten problem. Neviem preco sa dam dava -pi. Nejake napady ?
>>>>         
>> Co
>>     
>>>> robim/nerobim zle ?
>>>>
>>>> --
>>>>     Lukas "spark" Sandala
>>>>     icq#: 346552333
>>>>     jabber: spark@jabbim.sk
>>>>     e-mail: quazarstar@gmail.com
>>>>         
>
>
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-- 
    Lukas "spark" Sandala           
    icq#: 346552333                 
    jabber: spark@jabbim.sk
    e-mail: quazarstar@gmail.com