Generovani frekvence PICem

Jan Waclawek wek@evona.sk
Středa Březen 1 15:51:51 CET 2006


>>const times:array[0..119] of word = 
>>(26667,13333,8889,6667,5333,4444,3810,3333,2963,2667,2424,2222,2051,1905,1778,1667,1569,1481,1404,1333,1270,1212,1159,1111,1067,1026,988,952,920,889,860,833,808,784,762,741,721,702,684,667,650,635,620,606,593,580,567,556,544,533,523,513,503,494,485,476,468,460,452,444,437,430,423,417,410,404,398,392,386,381,376,370,365,360,356,351,346,342,338,333,329,325,321,317,314,310,307,303,300,296,293,290,287,284,281,278,275,272,269,267,264,261,259,256,254,252,249,247,245,242,240,238,236,234,232,230,228,226,224,222);
> 
> 
> To jse dal jen jako priklad? Nebo nejake realne hodnoty vami vypoctene 
> vztahujici se k memu problemu? Pokud ano tak rozdil mezi dvema 
> frekvencema na hornim konci nemuze byt dvojnasobne zpozdeni.
> 

No, vysiel som predsa z Vasej tabulky...
37.5Hz -> 26666.6666666us ->zaokr.-> 26667us
75Hz -> 13333.33333333us -> zaokr. -> 13333us
atd.

Tych 1.13% ste zrejme ziskali zaokruhlenim rozdielov, ktore ste sa z mne 
neznamych dovodov snazili udrzat monotonne; ale ja som zaokruhloval 
rovno periody. Tie rozdiely mi samozrejme potom chodia najma na tom 
hornom konci (2,2,3,3,3,2,3,3,3 atd. apod.) ale na tom hadam nezalezi, 
ci ano?

wek



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