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<div class="moz-cite-prefix">Rule 10.1 addresses a different issue.
It demands, among other things, that an expression which is
assigned to an unsigned variable should itself be unsigned. This
means that any constant or constant expression should itself be of
"unsigned" type - including the constant '0'. The rationale behind
this is that it is helpful to maintain consistent signedness when
constructing arithmetic expressions, even if the omission of a 'U'
suffix makes no difference to the result.</div>
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<div class="moz-cite-prefix">On 21.03.2021 19:16, Miroslav Draxal
wrote:<br>
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<p class="MsoNormal">Dobrý den,<o:p></o:p></p>
<p class="MsoNormal">Tak jsem na své projekty pustil MISRU2012.
Nestačím se divit. Zatím, co mě nejvíc udivuje, že 0 může být
signed i unsigned. Do teď jsem si myslel, že 0 je nic, nemá
žádné znaménko. Nebo je to jinak? U čísel !=0 je mi to jasné.
<o:p></o:p></p>
<p class="MsoNormal">Čili<o:p></o:p></p>
<p class="MsoNormal">unsigned u = (unsigned)0;<o:p></o:p></p>
<p class="MsoNormal">nebo<o:p></o:p></p>
<p class="MsoNormal">unsigned u = 0u;<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal">Míra<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
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<pre class="moz-signature" cols="72">--
Jindroush <a class="moz-txt-link-rfc2396E" href="mailto:jindroush@seznam.cz"><jindroush@seznam.cz></a></pre>
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