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<div class="moz-cite-prefix">&z+1 bude spatne, to bude dalsi
integer v poli, cili adresa +2 (nebo +4...)<br>
Nejdriv se musi ukazatel pretypovat na char* aby se indexovalo po
bytech<br>
<br>
Dne 23. 5. 2013 13:37, milger napsal(a):<br>
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<div class="moz-cite-prefix">za predpokladu ze som trafil endian
tak nejako takto predpokladam:<br>
x = *((char*) &z);<br>
y = *((char*)( &z+1));<br>
<br>
i ked som si to teskusil a moze tam byt chyba...<br>
<br>
Milan<br>
<br>
On 23. 5. 2013 13:28, Miroslav Draxal wrote:<br>
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<p class="MsoNormal">Dobrý den,<o:p></o:p></p>
<p class="MsoNormal"> int z= 0x1234;<o:p></o:p></p>
<p class="MsoNormal">char x,y<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal">Jak jednoduše dostat do char x hodnotu HI
bytu z int z (tj. 0x12) a do y dostat LO ze z (tj. 0x34)<o:p></o:p></p>
<p class="MsoNormal">Posuvem ano, přes pointery lze? – jenom
mě to tak napadlo a neumím najít řešení. Míra<o:p></o:p></p>
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