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<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff size=2>Dobry
den,</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff size=2>ze
dvou hodnout se to proste spociatat neda.</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff size=2>Pokud
narazite na shannon kotelnukuv vzorkovaci teorem, tak ten pracuje s
teoreticky</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff
size=2>nekonecnym poctem vzroku.</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff size=2>Pokud
vzrokujete tak musite dodrzet tuto nerovnost:</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff size=2>fsin
< fsam/2</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff size=2>Nebo
musite mit fazove rizene spousteni a vzrokovaci zesilovac.</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff
size=2>Prakticky, pokud dodrzite uvedenou nerovnost a matre moznost vzrokovat
delsi dobu, </FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff size=2>tak
amplituda bude rovna:</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff
size=2>MAX(samples) - MIN (samples)</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff
size=2>Samozrejme, ze nemusite vzrokovat do pole, ale max a min staci pocitat
pri cteni hodnot z prevodniku.</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=843011613-27012009> <FONT face=Arial
color=#0000ff size=2>Slavek</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=843011613-27012009><FONT face=Arial color=#0000ff size=2>PS:
Pozor na to, jak se chova AD prevodnik po dobu prevodu.</FONT></SPAN></DIV>
<DIV><SPAN class=843011613-27012009><!-- Converted from text/plain format -->
<P><FONT size=2>Ing. Slavomir Skopalik<BR>Jednatel spolecnosti<BR>Elekt Labs
s.r.o.<BR>Chaloupky 158<BR>783 72 Velky Tynec<BR>Czech
Republic<BR>--------------------------------------------<BR>Mobil: +420 724 207
851<BR>icq:199 118 333<BR>e-mail:skopalik@elektlabs.cz<BR><A
href="http://www.elektlabs.cz/">http://www.elektlabs.cz</A><BR></FONT></P></SPAN></DIV>
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<DIV class=OutlookMessageHeader lang=cs dir=ltr align=left><FONT face=Tahoma
size=2>-----Original Message-----<BR><B>From:</B> hw-list-bounces@list.hw.cz
[mailto:hw-list-bounces@list.hw.cz] <B>On Behalf Of </B>Dipl.-Ing. Michal
Kovácik<BR><B>Sent:</B> Tuesday, January 27, 2009 2:03 PM<BR><B>To:</B>
HW-news<BR><B>Subject:</B> velkost amplitudy sinusovky z dvoch hodnot
<BR><BR></FONT></DIV>
<DIV><FONT face=Arial size=2>Zdravim konferenciu. </FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Mam nasledovny problem. Vzorkujem sinusovku,
stihnem urobit len dve vzorky za jednu periodu a z nich potrebujem zistit
velkost amplitudy. </FONT></DIV>
<DIV><FONT face=Arial size=2>Viem, ze sa to da matematicky vypocitat, len
nikde nemozem najst nejaky pouzitelny vzorec alebo navod ako na
to.</FONT></DIV>
<DIV><FONT face=Arial size=2>Vie ma niekto nakopnut spravnym smerom?
</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Michal. </FONT></DIV>
<DIV> </DIV></BLOCKQUOTE></BODY></HTML>