RE: C: co lze oèekávat

[Jan Waclawek]

A ako sa prelozi

char arrayA[0x103] ;

int main(void) {
    volatile char x = 0;
    volatile char a = 3;
    x--;
    if (a != arrayA[x + 1]) {
            __builtin_software_breakpoint();
    }
    return 0;


? 

wek