ARM GCC - jak vytvořit neinicializovanou proměnnou v SDRAM

[Jaroslav Buchta]

Tak diky, zda se ze jsem nakonec nasel potrebnou informaci prave vcas ;-)

Jeste by me zajimalo, jestli by sly udelat inicializovane promenne i v 
ruznych pametovych prostorech, treba cast v SRAM a cast v SDRAM, musel 
by se upravit startup code, to je jasne, ale aby to prekladac nespojil 
do jednoho bloku vcetne par GB vyplne...



Dne 13. 10. 2014 21:37, Jan Smrz napsal(a):
> Zkuste v linker scriptu toto:
>
> .HeapMemSection (NOLOAD) :
>   {
>     *(.HeapMemSection*)
>   } >SDRAM
>
> J.S.
>
>
> Dne 13.10.2014 18:22, Jaroslav Buchta napsal(a):
>> Mám tuto definici:
>>
>> static volatile uint16_t SamplesBuf[3][100000]  __attribute__ 
>> ((section (".HeapMemSection")));
>>
>> ld script:
>> /* Specify the memory areas */
>> MEMORY
>> {
>>   FLASH (rx)      : ORIGIN = 0x08000000, LENGTH = 2048K
>>   RAM (xrw)       : ORIGIN = 0x20000000, LENGTH = 192K
>>   MEMORY_B1 (rx)  : ORIGIN = 0x60000000, LENGTH = 0K
>>   CCMRAM (rw)     : ORIGIN = 0x10000000, LENGTH = 64K
>>   SDRAM (rw)      : ORIGIN = 0xC0280000, LENGTH = 5632K
>> }
>> ....
>>   .HeapMemSection :
>>   {
>>     *(.HeapMemSection*)
>>   } >SDRAM
>>
>>
>> a ve výsledku to chce nacpat to pole i do Flash jako inicializovana data
>>
>>   text       data        bss        dec        hex    filename
>>  127116     627171      46356     800643      c3783 
>> bin/Debug/STM32F439-Test.elf
>>
>> skutecne je vysledny soubor .bin pres 3 GB.
>>
>> Uz mi to moc nemysli ani nehleda dneska, vysype to nekdo z rukavu?
>>
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