OT:patecni okenko x = y+++++y;

[Milan B.]

[xxxx na xxxx ~]# rm -f a.out ; grep "++" q.c ; gcc q.c ; ./a.out
x=y+ + ++(+y);
4 2

he he

-m-

On 4. 10. 2013 17:06, Jan Waclawek wrote:
> To y + + + y zatial nerozumiem, musim si to pozriet; ale s tym +++++ som si
> to pamatal, to je priamo v norme - C99, 6.4#6 EXAMPLE2 The program
> fragment x+++++y is parsed as x ++ ++ + y, which violates a constraint on
> increment operators, even though the parse x ++ + ++ y might yield a
> correct expression.
>
> Parser sa totiz podla 6.4#4 ma snazit najst najdlhsiu sekvenciu znakov,
> ktore sa daju vyhodnotit ako "nieco zmysluplne".
>
> Kvoli tomu je aj ten +++y vadny, ma sa to tiez parsovat ako ++ + y.
>
> wek
>